Uva 10371 Time Zones

題目來源：https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=15&page=show_problem&problem=1312


題意：

題目開頭先給你時區的簡稱，Input ：time  時區1  時區2

Output：將在時區1的time 換算成在時區2的time 並輸出


胡言亂語：

這題，卡在12小時制時間的換算超久QAQ

而函式的用法和#uva 860差不多XD

可以點進去看就好，先附上debug兩天...的程式碼~~~

...最後竟然是我把720打成780....

	#include<iostream>
	#include<cstring>
	#include<cstdio>
	#include<cstdlib>
	#include<iomanip>
	#include<map>
	using namespace std;
	map <string,double> table;
	void init(){
	table["UTC"] = 0 , table["GMT"] = 0;
	table["BST"] = 1 , table["IST"] = 1;
	table["WET"] = 0 , table["WEST"] = 1;
	table["CET"] = 1 , table["CEST"] = 2;
	table["EET"] = 2 , table["EEST"] = 3;
	table["MSK"] = 3 , table["MSD"] = 4;
	table["AST"] = -4 , table["ADT"] = -3;
	table["NST"] = -3.5 , table["NDT"] = -2.5;
	table["EST"] = -5, table["EDT"] = -4;
	table["CST"] = -6, table["CDT"] = -5;
	table["MST"] = -7, table["MDT"] = -6;
	table["PST"] = -8, table["PDT"] = -7;
	table["HST"] = -10, table["AKST"] = -9;
	table["AKDT"] = -8 , table["AEST"] = 10;
	table["AEDT"] = 11 , table["ACST"] = 9.5;
	table["ACDT"] = 10.5 , table["AWST"] = 8;
	}
	int main(){
	init();//建表
	int N,time,short_hand,long_hand;//時針、分針
	string st,local,outside;//a.m/p.m、當地時間、外地時間
	int tag;
	scanf("%d",&N);//讀入有幾筆測資
	cin.get();//讀掉換行字元
	while(N--){
	tag = 0;
	char *p, str1[100] ;
	cin.getline(str1,100);
	p = strtok(str1, " :");
	while (p != NULL) {
	tag++;
	if(tag==1){
	if(isdigit(*p)) short_hand = atof(p);
	else {
	tag = 3;
	if(!strcmp(p,"noon")) time = 12*60;
	if(!strcmp(p,"midnight")) time = 0;
	}
	}
	else if(tag==2) long_hand = atof(p);
	else if(tag==3) {
	time = long_hand+ short_hand*60;
	if(time>=720&&time<780) time-=720;
	if(!strcmp(p,"p.m.")) {
	time+=720;
	}
	}
	else if(tag==4) local = p;
	else if(tag==5) outside = p;
	p = strtok(NULL, " :");
	}
	time =time+ (table[outside]-table[local])*60+24*60;
	time %=1440;//因為time可能為負
	short_hand = (time/60)%24;
	long_hand = time%60;
	//printf("%d ",time);
	if(time == 0)
	printf("midnight\n");
	else if(time == 720)
	printf("noon\n");
	else{
	cout<<(time/60%12?time/60%12:12)<<":"<<setw(2)<<setfill('0')<<(time%60)<<" ";
	cout<<(time>720?"p.m.":"a.m.")<<endl;
	}
	}
	}

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